Sunday, August 17, 2014

Group 4 Experiment Day

Data

Organizing Plants
Plant Number Number of leaves Number of Mature Blooms Number of Immature Blooms
1A
30
1
2
2A
50
2
2
3A
25
1
2
4A
70
5
2
5A
30
2
3
AVERAGE
41
2.2
2.4
1B
65
3
3
2B
56
4
2
3B
72
2
6
4B
61
2
2
5B
54
1
3
AVERAGE
61.6
2.4
3.2
1C
35
2
3
2C
59
4
2
3C
60
3
2
4C
46
3
6
5C
29
2
3
AVERAGE
45.8
2.8
3.2
1D
30
2
3
2D
27
2
2
3D
59
5
4
4D
56
3
2
5D
14
1
2
AVERAGE
35.2
2.6
2.6
1E
28
2
2
2E
48
5
5
3E
13
1
2
4E
35
4
3
5E
62
5
0
AVERAGE
35.2
3.4
2.4

MATH:

Group A total of leaves (205) / 5 = (41) Average of leaves 
Group B total of leaves (308) / 5 = (61.6) Average of leaves 
Group C total of leaves (229) / 5 = (45.8) Average of leaves 
Group D total of leaves (186) / 5 = (35.2) Average of leaves 
Group E total of leaves (186) / 5 = (35.2) Average of leaves 

Group A total of mature blooms (11) / 5 = (2.2) Average of Mature Blooms 
Group B total of mature blooms (12) / 5 = (2.4) Average of Mature Blooms
Group C total of mature blooms (14) / 5 = (2.8) Average of Mature Blooms
Group D total of mature blooms (13) / 5 = (2.6) Average of Mature Blooms
Group E total of mature blooms (12) / 5 = (3.4) Average of Mature Blooms

Group A total of immature blooms(12) / 5= (2.4) Average of Immature Blooms
Group B total of immature blooms(16) / 5= (3.2) Average of Immature Blooms 
Group C total of immature blooms(16) / 5= (3.2) Average of Immature Blooms 
Group D total of immature blooms(13) / 5= (2.6) Average of Immature Blooms
Group E total of immature blooms(12) / 5= (2.4) Average of Immature Blooms


DATA COLLECTED

Trial 1


Initial CO2 Concentration  Final CO2 Concentration Change in CO2 Concentration
Container A (Blue) 150 ppm 1397 ppm +1247
Container B (Yellow) 150 ppm 1155 ppm +1005
Container C (Green) 100 ppm 802 ppm +702
Container D (Red) 100 ppm 910 ppm +810
Container E (Control) 160 ppm 803 ppm +643

MATH:
A: 1397 ppm - 150 ppm = 1247 ppm
B: 1155 ppm - 150 ppm = 1005 ppm
C: 802 ppm -100 ppm  = 702 ppm
D: 910 ppm - 100ppm = 810 ppm
E: 803 ppm - 160 ppm = 643 ppm

Trial 2


Initial CO2 Concentration  Final CO2 Concentration Change in CO2 Concentration
Container A (Blue) 308 ppm
991 ppm
+683
Container B (Yellow) 524 ppm
1167 ppm
+643
Container C (Green) 327 ppm
691 ppm
+364
Container D (Red) 592 ppm
931 ppm
+339
Container E (Control) 544 ppm
817 ppm
+273

MATH:
A: 991 ppm - 308 ppm = 683 ppm
B: 1167 ppm - 524 ppm = 643 ppm
C: 691 ppm - 327 ppm  = 364 ppm
D: 931 ppm - 592 ppm = 339 ppm
E: 817 ppm - 544 ppm = 273 ppm

Trial 3:

Initial CO2 Concentration  Final CO2 Concentration Change in CO2 Concentration
Container A (Blue) 313 ppm
831 ppm
+518 ppm
Container B (Yellow) 344 ppm
852 ppm
+507 ppm
Container C (Green) 233 ppm
392 ppm
+159 ppm
Container D (Red) 280 ppm
644 ppm
+364 ppm
Container E (Control) 270 ppm
473 ppm
+203 ppm

MATH:
A:831 ppm - 313 ppm = 518 ppm
B:852 ppm - 344 ppm = 507 ppm
C:392 ppm - 233 ppm = 159 ppm
D: 644 ppm - 280 ppm = 364 ppm
E: 473 ppm - 270 ppm = 203 ppm

 Trial 4:

Initial CO2 Concentration (ppm)  Final CO2 Concentration (ppm) Change in CO2 Concentration
Container A (Blue) 219 
932
713
Container B (Yellow) 234 
870
636
Container C (Green) 109 
617
508
Container D (Red) 167 
698
531
Container E (Control) 473 
593
410

MATH:
A:932 ppm - 219 ppm = 713 ppm
B: 870 ppm -  234 ppm = 636 ppm
C: 617 ppm - 109 ppm  = 508 ppm
D: 698 ppm -  167 ppm = 531 ppm
E: 593 ppm - 473 ppm = 410 ppm

Trial 5:

Initial CO2 Concentration  Final CO2 Concentration Change in CO2 Concentration
Container A (Blue) 385
955
570
Container B (Yellow) 313
901
588
Container C (Green) 258
656
398
Container D (Red) 311
758
447
Container E (Control) 321
609
288


MATH:
A:955 ppm -  385 ppm = 570 ppm
B:901 ppm -  313 ppm = 588 ppm
C: 656 ppm - 258 ppm  = 398 ppm
D: 758 ppm - 311 ppm = 447 ppm
E: 609 ppm- 321 ppm = 288 ppm

6 comments:

  1. Why did the plants decomposition make the results inconclusive? Couldn't you have used the average CO2 emission of the control plants to standardize this?

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    Replies
    1. All of the plants, (including the control plant) were covered in airtight containers and therefore underwent decomposition. So, no it would have been impossible to use the average CO2 emission of the control plants to standardize this. The plant's decomposition made the results inconclusive, because instead of decreasing CO2 levels (as should have occurred as the plants consumed the CO2) the levels increased and thus it was impossible to determine which light color allowed the plant to consume the most CO2. It would have been possible however, to determine which light color made the plant decompose (thus give off CO2) fastest.

      Delete
  2. How did you go about to make sure each light gave off the same amount of heat (knowing each light emits different watts)? What if the decomposition of the plant such a dramatic impact? Do you think your results would drastically change if they weren't placed in a different area?

    ReplyDelete
    Replies
    1. Since each flashlight was of the same wattage and same battery it should mean that the each plant received the same amount of time exposed to the source of light therefore the same amount of heat exposure. The decomposition of plants had such a dramatic impact on our results because the data resulted being inconclusive if decomposition wouldn't have occurred we assume that the blue light or the white light would have been best for photosynthesis. Our results could have changed if the plants were changed into larger containers containing relatively a larger amount of CO2 or changing the total light exposure to maybe just a pitch black room with the one source light could make results measurements more exact without regarding environmental factor that are sometimes uncontrollable.

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  3. Gabriel E. Hernandez (Student-Teacher with Amos)

    There are some groups that claimed to have found procedures that allowed them to extract chlorophyll from plants. I'm wondering if you could comment on how you might go about measuring carbon dioxide emission due to exposure of different light if you had a solution of chlorophyll extract.

    ReplyDelete
  4. If it were to just be the extraction of the chlorophyl then the procedures would be similar in that we would have a container of the extract and shine light on it and measure the CO2 response. But If we were to extract and isolate each pigment then we wouldn't be able to measure the CO2. When a light is shone on the extract, pigment molecules absorb energy.Since the pigments have been isolated from the thylakoid membranes of the chloroplasts, the energy cannot be used for photosynthesis and instead the energy is released as heat and light in a process called fluorescence. So we would end up measuring the red flourescence color produce or maybe the the tempearture change.

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